Question

How do you solve for x in `C=b-bx`?

Answer 1

See the entire solution process below:

Explanation:

First, subtract `color(red)(b)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`C - color(red)(b) = b - bx - color(red)(b)`

`C - b = b - color(red)(b) - bx`

`C - b = 0 - bx`

`C - b = -bx`

Now, divide each side of the equation by `color(red)(-b)` to solve for `x` while keeping the equation balanced:

`(C - b)/color(red)(-b) = (-bx)/color(red)(-b)`

`(C - b)/color(red)(-b) = (color(red)(cancel(color(black)(-b)))x)/cancel(color(red)(-b))`

`(C - b)/-b = x`

`x = (C - b)/-b`

Or

`x = C/-b - b/-b`

`x = -C/b + b/b`

`x = -C/b + 1`

`x = 1 - C/b`