How do you write the equation #y-2=3(x-1)# in slope intercept form?

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Answer 1 · 2017-02-11T02:57:05

#y = 3x - 1#

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

First, we need to expand the parenthesis on the right:

#y - 2 = (3 xx x) - (3 xx 1)#

#y - 2 = 3x - 3#

Now, add #color(red)(2)# to each side of the equation to solve for #y# while keeping the equation balanced:

#y - 2 + color(red)(2) = 3x - 3 + color(red)(2)#

#y - 0 = 3x - 1#

#y = color(red)(3)x - color(blue)(1)#