How do you solve #2(x+2)=3(x-8)#?

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Answer 1 · 2017-02-12T14:41:18

See the entire solution process below:

First, expand the terms in parenthesis on each side of the equation:

#(2 xx x) + (2 xx 2) = (3 xx x) - (3 xx 8)#

#2x + 4 = 3x - 24#

Now, subtract #color(red)(2x)# and add #color(blue)(24)# to each side of the equation to solve for #x#:

#2x + 4 - color(red)(2x) + color(blue)(24) = 3x - 24 - color(red)(2x) + color(blue)(24)#

#2x - color(red)(2x) + 4 + color(blue)(24) = 3x - color(red)(2x) - 24 + color(blue)(24)#

#0 + 28 = (3 - 2)x - 0#

#28 = 1x#

#28 = x#

#x = 28#