Question

How do you find the indefinite integral of `int -(5root3(x^2))/3dx`?

Answer 1

Rewrite the cube root as the `1/3` power and use the linear property of integration to move the constants outside the integral, then use the Power Rule

Explanation:

Rewrite the cube root as the `1/3` power and use the linear property of integration to move the constants outside the integral:

`int-(5root(3)(x^2))/3 = -5/3intx^(2/3)dx`

use the Power Rule for integrations, `intx^rdx = x^(r+1)/(r+1)+C`:

`-5/3intx^(2/3)dx = -5/3x^(5/3)/(5/3) + C`

`int-(5root(3)(x^2))/3 = -x^(5/3)+C`