How do you find the unit vector in the direction of the given vector of $w = i - 2 j$ $w=i-2j$ ?

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Answer 1 · 2017-02-18T09:43:37

$ˆ \to w = \frac{\sqrt{5}}{5} (\to i - 2 \to j)$ $" " hatvecw=sqrt5/5(veci-2vecj)$

$The unit vector in the direction of \to w$ $" The unit vector in the direction of " vecw$

$ˆ \to w = \frac{\to w}{∣ ∣ \to w ∣ ∣}$ $hatvecw=vecw/(|vecw|)$

$\to w = \to i - 2 \to j \Rightarrow ∣ ∣ \to w ∣ ∣ = \sqrt{1^{2} + 2^{2}} = \sqrt{5}$ $vecw=veci-2vecj=>|vecw|=sqrt(1^2+2^2)=sqrt5$

so $ˆ \to w = \frac{1}{\sqrt{5}} (\to i - 2 \to j)$ $" " hatvecw=1/sqrt5(veci-2vecj)$

$ˆ \to w = \frac{\sqrt{5}}{5} (\to i - 2 \to j)$ $" " hatvecw=sqrt5/5(veci-2vecj)$

How do you find the unit vector in the direction of the given vector of w=i-2jw=i−2jw=i-2j?