How do you factor #x^3+27=0#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Shwetank Mauria Feb 18, 2017 #(x+3)(x^2-3x+9)=0# Explanation: We have a standard polynomial on LHS of the form #a^3+b^3#, whose one factor is #(a+b)#. So one factor is #(x+3)# #x^3+27=0# #hArrx^3+3x^2-3x^2-9x+9x+27=0# or #x^2(x+3)-3x(x+3)+9(x+3)=0# or #(x+3)(x^2-3x+9)=0# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 8970 views around the world You can reuse this answer Creative Commons License