How do you find the vertex and the intercepts for #f(x)=(x+3)^2#?

1 Answer
Feb 20, 2017

#y# intercept=(0,3)
#x# intercept and also vertex=(-3,0)

Explanation:

When you have a question like this, it is very easy to find the vertex of the curve. We know that the line has equal roots so the vertex is -3 by making (#x#+3)=0. This also gives you the #x# intercept.

To find the #y# intercept, make #x# equal zero. You get the equation:

#y#=#x#(0)+3 hence #y#=3