How do you find the vertex of #f(x)=2(x-3)^2+1#?

1 Answer
Feb 21, 2017

vertex: #color(green)(""(3,1))#

Explanation:

The general quadratic vertex form is
#color(white)("XXX")f(x)=color(orange)m(x-color(red)a)^2+color(blue)b#
with vertex at #(color(red)a,color(blue)b)#

The given quadratic
#color(white)("XXX")f(x)=color(orange)2(x-color(red)3)^2+color(blue)1#
is a specific example of this vertex form
with vertex at #(color(red)3,color(blue)1)#