How do you change $y - \frac{2}{3} = - 2 (x - \frac{1}{4})$ $y - 2/3 = -2(x - 1/4)$ into slope intercept form?

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Answer 1 · 2017-02-26T08:24:32

Slope-intercept form is $y = m x + c$ $y = mx+c$

$y = - 2 x + 1 \frac{1}{6} or y = - 2 x + \frac{7}{6}$ $y = -2x+1 1/6" or " y = -2x+7/6$

$y - \frac{2}{3} = - 2 (x - \frac{1}{4})$ $y - 2/3 = -2(x-1/4)$

Follow the usual process of simplifying - start by getting rid of the brackets.

$y - \frac{2}{3} = - 2 x + \frac{1}{2}$ $y - 2/3 = -2x+1/2$

Slope-intercept form is $y = m x + c$ $" "y = mx +c" "$ so isolate the $y$ $y$ -term

$y = - 2 x + \frac{1}{2} + \frac{2}{3} \leftarrow$ $y= -2x+1/2+2/3" "larr$ add the fractions

$y = - 2 x + \frac{3 + 4}{6}$ $y = -2x +(3+4)/6$

$y = - 2 x + \frac{7}{6} or y = - 2 x + 1 \frac{1}{6}$ $y = -2x+7/6" or " y = -2x+1 1/6$

How do you change y - 2/3 = -2(x - 1/4)y−23=−2(x−14)y - 2/3 = -2(x - 1/4) into slope intercept form?