Question

What mass of sodium nitrate is required to give `128*g` of oxygen gas upon thermolysis of the salt?

Answer 1

Approx. `700*g`..........

Explanation:

We need a stoichiometric equation:

`NaNO_3(s) + Delta rarr NaNO_2(s) + 1/2O_2(g)`

We require a `128*g` mass of dioxygen gas, i.e. `(128*g)/(32.00*g*mol^-1)=4*mol`.

Given the equation, clearly we need AT LEAST `8*mol` of `"sodium nitrate"`, i.e. `8*molxx85.00*g*mol^-1=??g`