Question

How do you integrate `int 3 dt`?

Answer 1

`3t+C.`

Explanation:

We know that, for a const. `k, intkf(t)dt=kintf(t)dt.`

`:. int3dt=3intdt=3intt^0dt.`

Since, `intt^ndt=t^(n+1)/(n+1)+c, where, n!=-1,` we have,

`int3dt=3intt^0dt=3{t^(0+1)/(0+1)}=3(t^1/1)=3t+C.`