A solid disk with a radius of #5 m# and mass of #2 kg# is rotating on a frictionless surface. If #3 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #4 Hz#?

Question

1132 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-28T12:23:00

The torque is #=0.12Nm#

The power and the torque are related by the following equation

#P=tau omega#

Power #=3W#

The angular velocity #=4*2pi=8pirads^-1#

The torque is

#tau=P/omega=3/(8pi)=0.12Nm#