A vinegar-water solution is used to wash windows. If 1200L of a 28% solution are required, but only 16% and 36% solutions are available, how much of each should be mixed?

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Answer 1 · 2017-03-01T16:25:46

Volume of #16%# solution is #=480L#
Volume of #36%# solution is #=720L#

Let #V=# volume of #16%# solution

Then,

#(1200-V)# is the volume of the #36%# solution

Therefore,

We perform a material balance wrt vinegar

#1200*0.28=V*0.16+(1200-V)*0.36#

#336=0.16V+432-0.36V#

#0.36V-0.16V=432-336#

#0.20V=96#

#V=96/0.20=480L#

And,

#1200-480=720L#