How do you solve #9x+4=6x+8#?

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Answer 1 · 2017-03-01T18:17:53

See the entire solution process below:

First, subtract #color(red)(4)# and #color(blue)(6x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#9x + 4 - color(red)(4) - color(blue)(6x) = 6x + 8 - color(red)(4) - color(blue)(6x)#

#9x - color(blue)(6x) + 4 - color(red)(4) = 6x - color(blue)(6x) + 8 - color(red)(4)#

#3x + 0 = 0 + 4#

#3x = 4#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = 4/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 4/3#

#x = 4/3#