What is the vertex form of #2y=5x^2+4x+1 #?

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Answer 1 · 2017-03-03T07:34:32

The vertex form is #y=5/2(x+2/5)^2+1/10#

We perform this by completing the squares

#2y=5x^2+4x+1#

#y=5/2x^2+2x+1/2#

#y=5/2(x^2+4/5x)+1/2#

#y=5/2(x^2+4/5x+4/25)+1/2-2/5#

#y=5/2(x+2/5)^2+1/10#

This is the vertex form of the equation