Question

According to the following reaction, how many grams of hydrogen peroxide (`H_2O_2`) are necessary to form 0.182 moles oxygen gas?

hydrogen peroxide (`H_2O_2`) (aq) `->` water (l) + oxygen (g)

Answer 1

12.736 grams of hydrogen peroxide. please read explanation.

Explanation:

`2H_"2"O_"2"` `rarr` `2H_"2"O` + `O_"2"`

As per the mole ratio, 2 moles of hydrogen peroxide burns to form 1 mole of oxygen. The ratio is 2:1.
steps :

multiply 0.182 with 2 to find out total moles of hydrogen peroxide
answer = 0.364

to convert from moles to grams multiply the moles with molar mass
molar mass of hydrogen peroxide = 34

0.364*34 = 12.376 grams of hydrogen peroxide