Question

To what volume must 440.0 mL of 3.50 M `KNO_3` be diluted to produce 1.50 M `KNO_3`?

Answer 1

`C_1V_1=C_2V_2`

`V_2=" a bit over 1 litre"`

Explanation:

The product `C_1V_1` has units of `mol*cancel(L^-1)xxcancelL=mol`, and thus it is dimensionally consistent.

And `V_2=(C_1V_1)/C_2=(440.0*mLxx3.50*cancel(mol*L^-1))/(1.50*cancel(mol*L^-1))=??mL`