What is the vertex of the parabola #y=-x^2-2x+3#?
1 Answer
Explanation:
There is a lovely and straightforward (which makes it all the lovelier) rule for working out vertices such as this one.
Think of the general parabola:
The formula for finding the
Using your question
In this case:
#a=-1#
#b=-2# ; and
#c=3# .
To find the
#=(-(-2))/(2*(-1))=2/(-2)=-1#
So we now know that the
To find the
#y=-x^2-2x+3#
#y=-(-1)^2-2*(-1)+3#
#y=-1+2+3#
#y=4#
We now know that the
#(-1,4)#