Question

Question #fd7ab

Answer 1

First convert weight to moles

`"Moles" = "weight"/"molar mass"`

Therefore moles in 25g of aliminium

= `"25g"/"26.981539g/mol" = "0.926moles"`

If you had excess of chlorine

The amount of `AlCl_3` formed would be 0.926moles because the molar ratio of aluminium to aluminium trichloride = 2 : 2 = 1 : 1

If there would be 30g of chlorine then the amount of `AlCl_3` formed =

Moles in 30g of chlorine

= `"30g"/(35.453 * 2)= "0.42309536569moles"`

Balanced equation

= `2Al + 3Cl_2 = 2AlCl_3`

According to this aluminium is excess

Therefore aluminium needed`= " 0.4231mol"/("3mol" xx "2mol") = 0.28206357713"moles"`

Ratio of aluminium to aluminium trichloride

= 1 : 1

Therefore aluminium trichloride formed is 0.28206357713moles