How do you write the Vertex form equation of the parabola #y=2x^2+10+9#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Anjali G Mar 21, 2017 #y=2(x+5/2)^2-7/2# Explanation: Assuming you meant #10color(red)(x)#, not #10# #y=2x^2+10x+9# #y=2[x^2+5x+9/2]# #y=2[(x+5/2)^2-25/4+9/2]# #y=2[(x+5/2)^2-7/4]# #y=2(x+5/2)^2-7/2# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 950 views around the world You can reuse this answer Creative Commons License