A charge of #4 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #42 J# to #15 J#, what is the voltage between points A and B?

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Answer 1 · 2017-03-24T07:22:27

The voltage is #=6.75V#

The potential difference between the points #A# and #B# is #=U#

Voltage =Energy/Charge

#U=(DeltaE)/Q#

#DeltaE=42-15=27J#

The charge is #Q=4C#

#1 V=(1J)/C#

#U=27/4=6.75V#