How do you find the unit vector in the direction of the given vector of #u=<0,-2>#?

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Answer 1 · 2017-03-24T16:38:53

#hat u = langle 0, -1 rangle#

The unit vector, #hat u#, is:

#hat u = (vec u)/(abs ( vec u))#

And:

#abs ( vec u) = sqrt(0^2 + (-2)^2) = 2#

(But we knew that anyway as it only has a #mathbf j# component of magnitude 2.)

So:

#hat u = (langle 0, -2 rangle)/(2) = langle 0, -1 rangle#