Question #5231b

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Question #5231b

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Answer 1 · 2017-03-27T01:40:21

1.5 moles

Explanation:

Assuming you're referring to the decomposition reaction $2 {NaHCO}_{3} \to {Na}_{2} {CO}_{3} + H_{2} O + {CO}_{2}$ $2"NaHCO"_3rarr"Na"_2"CO"_3+"H"_2"O"+"CO"_2$ ,

$3.0 {mol NaHCO}_{3} \times \frac{1 {mol CO}_{2}}{2 {mol NaHCO}_{3}} = 1.5 {mol CO}_{2}$ $3.0"mol NaHCO"_3 xx (1"mol CO"_2)/(2"mol NaHCO"_3)=1.5"mol CO"_2$

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Question #5231b

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