Question

How do you find the slope and intercept of `y = 2/3 x`?

Answer 1

`m= 2/3 and c = 0`

Explanation:

In order to identify the slope and y-intercept from an equation of a straight line, it is easiest if it is the form `y =mx+c`

We have that form here: `y = 2/3x+0`

The slope is the numerical co-efficient of the x-term and the y-intercept is given by the constant term

`y = color(red)(m)x + color(blue)(c)`

`y = color(red)(2/3)x + color(blue)(0)`

Therefore the slope, `color(red)(m = 2/3)`

and the y-intercept is the point `color(blue)((0,0)`

Answer 2

`"slope "=2/3," y-intercept "=0`

Explanation:

The equation of a line in `color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`y=2/3x" is in this form as " y=2/3x+0`

`rArr"slope "=m=2/3" and y-intercept "=b=0`
graph{2/3x [-10, 10, -5, 5]}