What is the vertex form of #y= x^2+7x-30 #?

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Answer 1 · 2017-03-31T01:29:33

#(y + 89/4) = (x + 7/2)^2#

#y= x^2 + 7x - 10#
transpose -10 to the right side of the equation, from negative it will change its sign into positive

#y +10 = x^2 +7x#

Complete the square of the right side of the equation
Get half of the coefficient of x, then raise it to the second power.

Mathematically as follows: #(7/2)^2#= #49/4#

then add,
#49/4# to both sides of the equation

#y +10 + 49/4 = x^2 +7x + 49/4#
simplify the right side and factor the left side

#(y +89/4) = (x + 7/2)^2# #answer#