How do you find the GCF of $4 y, 18 y^{2}, 6 y^{3}$ $4y, 18y^2, 6y^3$ ?

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Answer 1 · 2017-03-31T11:31:39

See the solution process below:

The factors for each term are:

$4 y = 2 \cdot 2 \cdot y$ $4y = color(red)(2) * 2 * color(red)(y)$

$18 y^{2} = 2 \cdot 3 \cdot 3 \cdot y \cdot y$ $18y^2 = color(red)(2) * 3 * 3 * color(red)(y) * y$

$6 y^{3} = 2 \cdot 3 \cdot y \cdot y \cdot y$ $6y^3 = color(red)(2) * 3 * color(red)(y) * y * y$

Therefore, the GCF for the three terms is: $2 y$ $color(red)(2y)$

How do you find the GCF of 4y,18y2,6y34y, 18y^2, 6y^3?