Question

How many grams of CO are needed to to produce 442 grams of Fe? `1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe`

Answer 1

331.5 g of CO are needed.

Explanation:

#n mol Fe = m/( MW) = (442 g)/(56 g/(mol)) = 7.89 mol#

`n mol CO = 7.89 mol Fe * ((3 mol CO)/(2 mol Fe)) = 11.84 mol CO`

`mass CO = n * MW = 11.84 mol * (28 g)/(mol) = 331.5 g CO`