How do you simplify #sqrt( 14-a) =sqrt( a+3) +3#?

Question

1218 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T14:02:45

I have taken you step by step to a point where you may take over.
A lot of detail is given.

Square both sides

#14-a=(a+3)+6sqrt(a+3)+9#

Subtract #(a+3)# from both sides

#11-2a=6sqrt(a+3)+9#

Subtract 9 from both sides

#2-2a=6sqrt(a+3)#

Divide both sides by 6

#1/3-a/3=sqrt(a+3)#

Square both sides

#1/9-2/3(a/3)+a^2/9=a+3#

#-26/9-(2a)/9-(9a)/9+a^2/9=0#

#-26/9-(11a)/9+a^2/9=0#

#-26-11a+a^2=0#