How do you write #y=x^2-10x+4# in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Apr 10, 2017 In vertex form : #y= (x-5)^2 -21 # Explanation: #y= x^2 -10x +4 or y= x^2 -10x + 25 -25+4 = (x-5)^2 -21 # Vertex is at #(5,-21)#. [Compare with standard form #y=a(x-h)^2+k ; (h,k) # is vertex] graph{x^2-10x+4 [-80, 80, -40, 40]} [Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 6068 views around the world You can reuse this answer Creative Commons License