What is the equation of the line with slope # m= -13/5 # that passes through # (-23,16) #?

1 Answer
Apr 17, 2017

See the entire solution process below:

Explanation:

We can use the point-slope formula to find the equation of the line meeting the criteria in the problem. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the slope and values for the point from the problem gives:

#(y - color(red)(16)) = color(blue)(-13/5)(x - color(red)(-23))#

#(y - color(red)(16)) = color(blue)(-13/5)(x + color(red)(23))#

We can also solve for #y# to find the equation in slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y - color(red)(16) = (color(blue)(-13/5) xx x) + (color(blue)(-13/5) xx color(red)(23))#

#y - color(red)(16) = -13/5x - 299/5#

#y - color(red)(16) + 16 = -13/5x - 299/5 + 16#

#y - 0 = -13/5x - 299/5 + (16 xx 5/5)#

#y = -13/5x - 299/5 + 80/5#

#y = color(red)(-13/5)x - color(blue)(219/5)#