A 15.00 mL solution of potassium nitrate (KNO3) was diluted to 125.0 mL, and 25.00 mL of this solution were then diluted to 1.000 x 10^3 mL. The concentration of the final solution is 0.00383 M. What is the molarity of the original solution?

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Answer 1 · 2017-04-25T02:09:38

#"Molarity of original solution" = 1.277M#

Solution 1: 15.00mL
Solution 2: 125.0mL
Solution 3: 25.00mL
Solution 4: 1000.mL

#"mols Solution 4" = 1000.mL * 0.00383M = color(teal)(0.00383 mols)#

#"Molarity Solution 3" = color(teal)(0.00383 mols)/(25.00mL) = color(purple)(0.1532M)#

#"mols Solution 2" = color(purple)(0.1532M) * 125.0mL = color(orchid)(0.01915 mols)#

#"Molarity Solution 1" = color(orchid)(0.01915 mols)/(15.00mL) = color(salmon)(1.276666667M)#

#"Molarity of original solution" = color(salmon)(1.277M)#