Question

Question #51377

Answer 1

This will require 2.067 litres of the acid solution.

Explanation:

In the equation, we see that 3 moles of `H_2` are produced when 3 moles of `H_2SO_4` are reacted. (This is seen from the coefficients placed before these formulas.)

To simply the relation, we can say that the ratio between `H_2SO_4` used and `H_2` produced is 1-to-1.

Now, we must convert the mass of `H_2` into moles:

`25.0 g -: 2.01588 g/"mol" = 12.40 "mol"`

Since the ratio is 1-to-1, this means we will require 12.40 mol of `H_2SO_4` to produce this hydrogen gas.

To determine the volume of the solution required, we start with the definition of molarity:

`"Molarity" = ("moles of solute")/("litres of solution")`

So,

`"litres of solution" = ("moles of solute")/("molarity") = (12.4 "mol")/(6.00 "mol"/L) = 2.067 L`