Question

What occurs when a `190*mL` volume of barium nitrate at `0.105*mol*L^-1` concentration is mixed with `170*mL` volume of sodium sulfate at `0.100*mol*L^-1` concentration?

Answer 1

`"Barium sulfate"` is a water insoluble salt.

Explanation:

The stoichiometric reaction is:

`Ba^(2+) + SO_4^(2-) rarr BaSO_4(s)darr`

And so we work out the molar equivalence of barium and sulfate ions.

`"Moles of sulfate ion"-=170xx10^-3Lxx0.100*mol*L^-1=0.0170*mol.`

`"Moles of barium ion"-=190xx10^-3Lxx0.105*mol*L^-1=0.01995*mol.`

And thus, clearly, sulfate dianion is the limiting reagent. And `0.0170*mol` `BaSO_4` should precipitate as a white solid. This represents a mass of................

`0.0170*cancel(mol)xx233.43*g*cancel(mol^-1)=3.96*g`.