What is the vertex form of # f(x) = -5x^2-x-12 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer 冠廷 李. Apr 29, 2017 #f(x)=-5(x+1/10)^2-239/20# Explanation: #f(x)=-5(x^2+1/5x)-12# #=-5(x^2+1/5x+1/100)-12+1/20# #=-5(x+1/10)^2-239/20# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1611 views around the world You can reuse this answer Creative Commons License