Question

How do you find the axis of symmetry, and the maximum or minimum value of the function `x = 1/32 y^2`?

Answer 1

Axis of symmetry is `y=0`, vertex is `(0,0)` and there is no maximum or minimum.

Explanation:

As the equation of the form `x=a(y-k)^2+h`, whose axis of symmetry is `y=k` and vertex is `(h,k)`. In this form of equation of parabola, there is no maximum or minimum.

As `x=1/32y^2hArrx=1/32(y-0)^2+0` axis of symmetry is `y=0` and vertex is `(0,0)` and there is no maximum or minimum.

graph{x=1/32y^2 [-27.33, 52.67, -20.64, 19.36]}