Question

How do you find the value for `sin[2cos^(-1)(3/5)]`?

Answer 1

`24/25`

Explanation:

`sin[2 cos^-1(3/5)] =2 sin(cos^-1(3/5)cos(cos^-1(3/5)`
`= 2*3/5(sqrt(1 - (3/5)^2)`
`= 6/5*4/5`
`= 24/25`