Question

What mass of water results from complete combustion of a `576*g` mass of propane?

Answer 1

`C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l) + Delta`

Explanation:

Is the equation balanced? It must be if it represents physical reality. What does `Delta` mean?

And thus each mole of propane results in FOUR moles of water upon complete combustion........

And so we set up the stoichiometric ratio:

`(576*g)/(44.1*g*mol^-1)xx18.01*g*mol^-1xx4=235*g` water........