Question

Question #02722

Answer 1

f.wt. = 125 g/mole

Explanation:

Assume the following acid/base rxn

HA + NaOH => NaA + HOH
Rxn is 1:1 mole ratio of HA:HOH which means that moles of acid will be completely neutralized by an equal number of moles of base. That is ...

moles acid neutralized = moles of base used

moles = mass(g)/formula wt and in solution, moles = Molarity x Volume in Liters

Given:
`"moles" of HA = 0.25 "grams" / "f.wt. of acid"`
moles of NaOH = `((0.20 mol)/(dL)^3)(0.010Liters)` = `((0.20 mol)/L)(0.010L)` = `0.002 "mole"`

using moles acid = moles base

`(0.25 grams)/(f.wt acid)` = `(0.002"mole")`

f.wt acid = `(0.25 g)/((0.002"mole")` = `125 g/"mol"`