How do you solve #5( 6+ 3f ) = - 2( 3- 3f )#?

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Answer 1 · 2017-05-22T20:31:36

#f= - 4#

Multiply #5# to #(6+3f)#. It will give

#30 + 15f#

On the other side, multiply #-2# to #(3-3f)#. It will give

#-6 + 6f#

So,

#30 +15f = -6 + 6f#

Bring the #f# terms on one side

#15f - 6f = -6 + -30#

#9f = -36#

Now divide each side by #9#

#f= -36/9#

#f= - 4#