Question

Question #9ca43

Answer 1

`1.83 "mol Fe"_2"O"_3`

Explanation:

We can solve this problem by converting the given mass of `"Al"` to moles, and then use the stoichiometric relationships (the coefficients) in the chemical equation to convert to moles of `"Fe"_2"O"_3`:

`99.0cancel("g Al")((1 cancel("mol Al"))/(26.98 cancel("g Al")))((1 "mol Fe"_2"O"_3)/(2 cancel("mol Al"))) = color(red)(1.83 "mol Fe"_2"O"_3`