What is the slope of the line -2x-5y=11?

2 Answers
May 26, 2017

See a solution process below:

Explanation:

We can transform this line to the Standard Form for Linear Equations. The standard form of a linear equation is: color(red)(A)x + color(blue)(B)y = color(green)(C)

Where, if at all possible, color(red)(A), color(blue)(B), and color(green)(C)are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

To transform this equation we need to multiply each side of the equation by color(red)(-1) to ensure the coefficient for x is positive while keeping the equation balanced:

color(red)(-1)(-2x - 5y) = color(red)(-1) xx 11

(color(red)(-1) xx -2x) + (color(red)(-1) xx - 5y) = -11

color(red)(2)x + color(blue)(5)y = color(green)(-11)

The slope of an equation in standard form is: m = -color(red)(A)/color(blue)(B)

Substituting the x and y coefficients gives:

m = -color(red)(2)/color(blue)(5)

May 26, 2017

The slope is -2/5.

Explanation:

Find the slope:

-2x-5y=11

Solve for y, which will give you the slope intercept form of a linear equation: y=mx+b, where m is the slope and b is the y-intercept.

Add 2x to both sides of the equation.

-color(red)cancel(color(black)(2x))+color(red)cancel(color(black)(2x))-5y=2x+11

Simplify.

-5y=2x+11

Divide both sides by -5.

(color(red)cancel(color(black)(-5))y)/(color(red)cancel(color(black)(-5)))=-2/5x-11/5

Slope intercept form.

y=-2/5x-11

The slope is -2/5