How do you write y=x^2+16x+14 in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Justin May 27, 2017 y = (x+8)^2 -50 Explanation: By completing the square: y = x^2 + 16x + (16/2)^2 - (16/2)^2 + 14 y = (x+8)^2 - 64 + 14 y = (x+8)^2 -50 Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3827 views around the world You can reuse this answer Creative Commons License