Question

If 6.5 grams of CO react, how many liters of `CO_2` are produce?

Answer 1

You need to specify standard conditions of temperature and pressure, for instance, `1*atm`, and `298*K`.....and get approx. `160*L`

Explanation:

Now carbon monoxide oxidizes to give the same molar quantity of `CO_2`:

`CO(g) + 1/2O_2(g) rarr CO_2(g)`

Given the Ideal Gas Equation........

`V=(nRT)/P=((6.5*g)/(28.01*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx298*K)/(1*atm)`

`~=160*L`.

Pressure is a state function of temperature, amount of gas, and volume, so we must make these extra assumptions to answer the question.