How do you factor 8x^3 - 8x^2 - x + 1 by grouping? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer SagarStudy Jun 9, 2017 8x^3-8x^2-x+1 Take 8x^2 common from first two terms and -1 from the last two terms. =8x^2(x-1)-1(x-1) Take the factor (x-1) as common. =(x-1)(8x^2-1) Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor 2x+2y+ax+ay? How do you factor 3x^2+8x+4 by using the grouping method? How do you factor 6x^2-9x+10x-15? How do you group and factor 4jk-8j^2+5k-10j? What are the factors of 2m^3+3m^2+4m+6? How do you factor quadratics by using the grouping method? How do you factor x^4-2x^3+5x-10? See all questions in Factoring by Grouping Impact of this question 2000 views around the world You can reuse this answer Creative Commons License