Well, what's the configuration of #"H"# plus one electron? #"H"# notoriously has only one electron... and it is in the #1s# orbital, the first orbital of #n = 1# and #l = 0#. Therefore, its electron configuration can only be #1s^1#.
...and #"H"^(-)# has #1 + 1 = 2# electrons by conservation of charge... so #1s^?# is the electron configuration?