How do you write a quadratic equation with vertex; ( 2,-2 ); point: ( 4,10 )?

1 Answer
Jun 10, 2017

The vertex form of a quadratic with vertex #(h,k)# looks like this:

#y = a(x-h)^2+k#

In this case, we already know #h = 2# and #k=-2#, so our equation is:

#y = a(x-2)^2-2#

So all we have to do is find #a#. We can do this by plugging in the other point #(color(red)4,color(blue)10)# we were given (which we know works since it is on the parabola) and solving for #a#.

#color(blue)10 = a(color(red)4-2)^2-2#

#10 = a*2^2 - 2#

#10 = 4a-2#

#12 = 4a#

#3 = a#

Therefore, our equation is:

#y = 3(x-2)^2-2#

Final Answer