How do you write the equation #y-5=6(x+1)# in slope intercept form?

1 Answer
Jun 12, 2017

See a solution process below:

Explanation:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#y - 5 = color(red)(6)(x + 1)#

#y - 5 = (color(red)(6) xx x) + (color(red)(6) xx 1)#

#y - 5 = 6x + 6#

Now, add #color(red)(5)# to each side of the equation to solve for #y# while keeping the equation balanced:

#y - 5 + color(red)(5) = 6x + 6 + color(red)(5)#

#y - 0 = 6x + 11#

#y = color(red)(6)x + color(blue)(11)#