Question

Given EXCESS zinc metal, what volume of dihydrogen gas at `"NTP"` will be evolved from the action of `500*cm^3` of `H_2SO_4` at `0.50*mol*L^-1` concentration?

Answer 1

We interrogate the redox reaction......

`Zn(s) + H_2SO_4(aq) rarr ZnSO_4(aq) + H_2(g)uarr`

Explanation:

And thus ONE equiv of dihydrogen results from each equiv of sulfuric acid (and also from each equiv of zinc metal).........

As far as I know `"NTP"` specifies `1*atm` pressure and `293.15*K`, and the molar volume of an Ideal Gas at `NTP` is `24.05*L`

`"Moles of sulfuric acid"=500*cm^3xx10^-3*L*cm^-3xx0.5*mol*L^-1=0.25*mol`

And thus `0.25*mol` dihydrogen gas will be evolved.

And so volume at `"NTP"=0.25*molxx24.05*L*mol^-1~=6*L`