How do you write the equation of the parabola in vertex form given vertex (0,0) and the directrix y=-16?
1 Answer
Jul 2, 2017
#y=1/64 x^2#
Explanation:
Given -
Vertex
Directrix
Focus
The Parabola is opening up, as its directrix is
The formula for the parabola in the vertex form is -
#(x-h)^2=4.a.(y-k)^2#
Where -
#h = 0# x-coordinate of the vertex
#k=0# y-coordinate of the vertex
#a=16# distance between vertex and focus
#x-0)^2=4xx16(y-0)#
#x^2=64y#
#y=1/64 x^2#