For #Z=57#, what is the element, and what is its electronic configuration?

1 Answer
anor277
Jul 5, 2017

Got a Periodic Table............?

Explanation:

I actually happen to know this one, because I did a lot of work with lanthanides, and actinides. Anyway, #Z=57# SPECIFIES the element #"lanthanum"#. And thus the electronic configuration has an xenon core (#Xe, Z=54#), i.e. #[Xe]5d^(1)6s^(2)#. Lanthanum usually adopts the #+III# oxidation state, i.e. #{[Xe]}^(3+)#.....

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